Properties 1, 2 follow from the properties of real numbers. Property 3 follows from the definition of a zero-matrix. Property 4 Let A, B, and C be three matrices such that all multiplications are appropriate. Then (AB)C = A(BC). Proof: We have to show that the corresponding elements of matrices (AB)C and A(BC) are equal. By the definition, the element on the i-th row and the k-th column of the product AB is Then the element on the i-th row and the j-th column of the product (AB)C is Changing the order of summation, we obtain The equality of the corresponding matrix elements implies the equality of the matrices. Property 5 Let A and B be two matrices such that the product AB is defined. Then Proof: Consider the element on the i-th row and the j-th column of the matrix ![]() Thus, each element of Property 6 Let A be a AE = A. Proof: We need to show that each element of AE is equal to the corresponding element of A. Consider the element on the i-th row and the j-th column of the matrix AE. By the property of the Kronecker delta symbol, we have for each pair of indexes {i, j}. Hence, the desired statement AE = A. If A is a square matrix then we can also perform the product EA:
Property 1 Let A, B, and C be three matrices such that the corresponding products and sums are defined. Then A(B + C) = AB + AC and (A + B)C = AC + BC. Proof: Consider the element on the i-th row and the j-th column of the matrix ![]() for each pair of indexes {i, j}. Therefore, the matrices A(B + C) and (AB + AC) are equal. The equality of the matrices (A + B)C and (AC + BC) can be proven just in the same way: Property 2 follows from the properties of real numbers. The proof can be performed by the reader. |